You are planning to use a sample proportion p to estimate a population proportion, p. A sample size of 100 and a confidence level of 95% yielded a margin of error of 0.025. Which of the following will result in a larger margin of error? A: Increasing the sample size while keeping the same confidence level B: Decreasing the sample size while keeping the same confidence level C: Increasing the confidence level while keeping the same sample size D: Decreasing the confidence level while keeping the same sample size

A) A and D
B) A and C
Q) B and D
D) B and C

option c) B AND D

Step-by-step explanation: the confidence level and sample size have an inverse relationship that affects marginal error.

Firstly, marginal error is indirectly proportional to sample size which implies that a larger sample size gives a better approximation of the population that a small sample size.

The confidence level is the level at which a test is being performed to produce the best result.

It is the the level that states the authenticity of a claim and backs it up.

Hence If you are going to be reducing your confidence level, it means you are increasing your chance of making marginal error, hence you have to make up for this by increasing the sample size.

And if you want to reduce your sample size, you will also bring in a large value of marginal error, you can make up for this by increasing your confidence level.

For option C, if you keep increasing your confidence level but keep a constant value of sample size you will be reducing marginal error.

For option A, if you keep increasing your sample size but have a constant confidence interval, your marginal error will reduce.

Option B and D will increase marginal error

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;