Find parametric equations for the tangent line to the given curve at the point(213252656). The curve and the tangent line must have the same velocity vector at this point.

x(t)=1+4ty(t)=3t32?2tz(t)=4t2+6t+6
x(t)=
y(t)=
z(t)=
Give the unit tangent vector to the curve at (213252656)
T=

282 6/7 cm^2

step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)

mathpapa

step-by-step explanation: