. A softball coach has 2 buckets of balls. One contains 15 new and 5 used balls. The second bucket contains 2 new and 8 used balls. The coach randomly selects a bucket and then randomly selects a ball from the bucket. a. Find the probability that the ball selected is new. b. Given that the coach selects a used ball, find the probability the ball is from the first bucket.

a) the probability that the ball selected is new is 0.475

b) the probability the ball is from the first bucket is 0.2381

Step-by-step explanation:

A = the ball selected is new

B = the bucket selected by the coach is de first one.

P(A|B) = 15/(15+5)=0.75

P(A|B') = 2/(2+8)=0.2

P(B) = 0.5

a) by the total probability theorem

P(A) = P(A∩B) +P(A∩B') = P(A|B)*P(B) + P(A|B')*P(B') = 0.75*0.5+0.2*(1-0.5)=0.475

b) by the bayes rule

P(B|A')=P(A'|B)P(B)/P(A') = (1-0.75)*0.5/(1-0.475)=0.2381

283 square feet

step-by-step explanation:

good luck

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!