C240
Problem 2:
in simple interest, a sum of money amounts to $ 6200 in 2 years and $ 7400 in 3 years Find the
principal

What is the answer and how do I do it.

  $3800

Step-by-step explanation:

When simple interest is added to the principal amount, the sum increases linearly with time. Essentially, you are asked for the y-intercept of a line that goes through the points (2, 6200) and (3, 7400). You can use the 2-point form of the equation of a line to find it:

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (7400 -6200)/(3 -2)(x -2) +6200 . . . . fill in given points

  y = 1200(x -2) +6200 . . . . . . . . . simplify some

  y = 1200x -2400 +6200 . . . . . . simplify more

  y = 1200x +3800 . . . . . . . . . . . . . completely simplify

When the number of years (x) is zero, the amount is 3800. The principal is $3800.

The account is earning $1200 per year on a principal of $3800. The interest rate is about 31.6%, an unusually high value.

Alternate solution

You can recognize that the interest earned in one year is 7400 -6200 = 1200. Since this is simple interest, the amount of interest earned each year is the same, so in 3 years, the account has earned 3×$1200 = $3600 in interest. Then the original principal amount must be ...

  $7400 -3600 = $3800 . . . . . principal amount

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation: