Greyhounds can reach speeds of 20.1 meters per second. Which conversion factor can be used to find this speed in meters per minute?

StartFraction 1 minutes Over 60 seconds EndFraction
StartFraction 1 second Over 60 minutes EndFraction
StartFraction 60 seconds Over 1 minute EndFraction
StartFraction 60 minutes Over 1 second EndFraction

Step-by-step explanation:

20.1metres / seconds

We want to convert to metres /minutes

It is known that 60seconds=1minutes

So therefore, either we multiply 20.1metres/seconds by

60seconds/1minutes

Or

1minutes/60seconds

Multiplying with the above does not change the magnitude of the quantity because it is like we are multiplying by 1.

Since we want to cancel seconds and it is in the denominator, so to do this we need to multiply with the fraction that has the seconds as numerator.

So, we are going to multiply with 60seconds/1minutes

20.1metres/seconds ×60seconds/minutes

1206metres/minutes.

So the correct fraction is the StartFraction 60 seconds Over 1 minute, which is the third option

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.