Choose an American adult at random. The probability that you choose a woman is 0.52 . 0.52. The probability that the person you choose has never married is 0.26 . 0.26. The probability that you choose a woman who has never married is 0.11 . The probability that the person you choose is either a woman or has never been married (or both) is therefore about:

(a) 0.77.
(b) 0.66.
(c) 0.44.
(d) 0.38.
(e) 0.13.

The probability that the person you choose is either a woman or has never been married (or both) is therefore about 0.66

Step-by-step explanation:

Given Data:

Probability of choosing a women = P(W) = 0.52

Probability that chosen person has never married = P(M) = 0.26

Probability of choosing a women that has never married = P(W and M) = 0.11

We need to find the probability that the person you choose is either a woman or has never been married (or both). The addition rule of probabilities of two events is given as:

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) is the probability of occurrence of either A or B or both. P(A and B) is the probability of occurrence of A and B at the same time.

Re-writing the addition formula for given case, we get:

P(W or M) = P(W) + P(M) - P(W and M)

Substituting the given values results in:

P(W or M) = 0.52 + 0.26 - 0.11

P(W or M) = 0.67

Therefore, the probability that the person you choose is either a woman or has never been married (or both) is 0.67.

Note: There is either typo in given options or the questions. The question I found on Google has 0.25 as the probability that the person you choose has never married ( i.e. P(M) = 0.25 ).

So, in this case the correct answer would be option (b) 0.66

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy

your exact question is kind of difficult to understand, so maybe an example will explain what you're supposed to do? i'll work through the first problem on the worksheet.

suppose you have a tray of 652 brownies, and you have 5 friends that you want to feed without picking favorites. how many brownies can you dole out to each of your friends in equal amounts? how many will be left over for you to eat?

what you're doing here is finding a way to arrange the number 652 as the sum of integer multiple of 5 and some remainder:

here ("q" for quotient) is the number of brownies each of your friends get, and is the remainder. that's the basic idea behind division.

we break up the number 652 into parts so that the leading digit stands on its own:

652 = 600 + 52

first we check if it's possible to hand out exactly 100 brownies to each friend. with 5 friends, this means we want to know if we can take out 500 brownies from the tray. we can do this 1 time because we have 600 brownies to take from, and when we do that we're left with 100 + 52 brownies to divvy up. so we know that

652 = 1*500 + 152

next we want to know if it's possible to hand out exactly 10 brownies per friend. if we can, we have to remove 50 brownies from the tray each time until we can't. we have 152 brownies left, and we know that 3(50) = 150, so

152 = 3*50 + 2

now we have 2 brownies left in the tray. is it possible to hand 1 out to each of your 5 friends? no, you'd need a minimum of 5 brownies to do that. so the last 2 are yours.

putting everything together, we found that

652 = 1*500 + 3*50 + 2

and we can rearrange this to write

652 = 5*100 + 5*30 + 2

652 = 5(100 + 30) + 2

652 = 5*130 + 2

so and .

you might be more accustomed to the table depicting the algorithm. that's just a compact way of organizing what we've done above. you can consult the image i've attached below.