Find the probability that when a couple has six children, at least one of them is a girl. (Assume that boys and girls are equally likely.)

Pr(at least a girl) =          

Step-by-step explanation:

Probability = Number of required outcomes / number of possible outcomes

We are to find the probability of at least one girl. assuming the likelihood of boys and girls are equal.

Pr( boy) =

Pr (three boys) = Pr(boy) * Pr(boy)  *Pr (boy)

                         =0.5*0.5*0.5

                         =0.125

Pr ( at least a girl) = Pr (not getting a boy)

Pr(at least a girl) = 1- Pr(three boys)

Pr(at least a girl) = 1-0.125

Pr(at least a girl) = 0.875

Pr(at least a girl) =          

step-by-step explanation: step 3 should really go to step seven, but anyway never mind.

1 ∠oln ≅ ∠lno

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x