Y′=3cos(t)−6y, y(0)=0 (a) Find approximate values of the solution of the given initial value problem at t= 0.1, 0.2, 0.3, and 0.4 using the Euler method with h=0.1. Round your answers to three decimal places. y(0.1)≈ y(0.2)≈ y(0.3)≈ y(0.4)≈ (d) Find the solution y=φ(t) of the given problem and evaluate φ(t) at t= 0.1, 0.2, 0.3, and 0.4. Enclose arguments of functions in parentheses. For example, sin(2x).

i think it will be 4feet long of what i comprehend

  b:   ∠x = 28.6°, ∠y = 31.2°, ∠z = 120.2°

step-by-step explanation:

this is one of those questions where "test taking skill" is all you need. the only answer that has angles that sum to 180° is the one shown above. the remaining choices do not describe the angles of a triangle.

if you want to do more work than simply adding the offered numbers, you can also check them against the law of sines. it should be true that

  x/sin(x) = y/sin(y) = z/sin(z)

and all of these ratios must be greater than 15, the longest side length.

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if you want to solve the triangle from scratch, i'd suggest solving for the largest angle using the law of cosines.

  z² = x² +y² -2xy·cos(z)

  z = arccos((x² +y² -z²)/(2xy)) = arccos(-75.11/149.4) = 120.182°

now you can find y from the law of sines

  y = arcsin(y/z·sin(z)) = 31.242°

y=5

step-by-step explanation:

josh is incorrect

x= 7 and x= -1

step 2 is wrong and honestly first step is not needed, you just need to figure out the factors

i know its wrong because if you plug in the solutions josh found, they do not work (in the original equation)

x^2 -6x -7 = 0

(x-7) (x+1) = 0

x-7=0 x+1=0

x= 7 x= -1