PLEASE HELP ME OUT
Solve the following simultaneous linear and quadratic equation ( this means that when you start solving the equation, you get to a point that is quadratic, then you solve it the quadratic way . )
(1) x-3y=2 and x^2+2y^2=3
( 2 ) 2x-y = 6 and xy + y = 24
( 3 ) 3x-y =- 4 and x^2+3y^2=16
Please I really need it by tomorrow afternoon.

the answer is 37

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

98%

step-by-step explanation:

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation: