Consider the function give below
f(x)={ 0, x less then or equal to -2
{ sin 1/x+2 , x> -2
does the lim x->-2+ exist?

The Limit doesn't exist

Step-by-step explanation:

One-Sided Limit

It's the term that describes when the limit of a function is computed as the variable approaches to a value from the right or from the left side.

They are expressed respectively as

We have a function defined by pieces

f(x)=0 if

f(x)=sin(1/x)+2 if x > -2

For the limit when x approaches to -2 to exist, both one-sided limits must exist and be equal. Let's test the left-side limit

Now for the right-side limit

Since both limits are different, the required limit does not exist

the temperature will be -18 just do 62 + (-40) + (-40)

step-by-step explanation:

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.