Someone help me please.

Step-by-step explanation:

f(x) = -0.01x² + 0.7x + 6.1

a) f(x) is a downward facing parabola, so the maximum height is at the vertex.  The vertex of a parabola can be found using x = -b/(2a).

x = -0.7 / (2 × -0.01)

x = 35

f(35) = -0.01(35)² + 0.7(35) + 6.1

f(35) = 18.35

The maximum height is 18.35 feet.

b) The maximum horizontal distance is when the ball lands, or when f(x) = 0.

0 = -0.01x² + 0.7x + 6.1

0 = x² − 70x − 610

Solve with quadratic formula:

x = [ -b ± √(b² − 4ac) ] / 2a

x = [ -(-70) ± √((-70)² − 4(1)(-610)) ] / 2(1)

x = (70 ± √7340) / 2

x = 35 ± √1835

x = -7.84, 77.84

x can't be negative, so x = 77.84.  The ball's maximum horizontal distance is 77.84 feet.

c) When the ball is first launched, x = 0.  The height at that position is:

f(0) = 6.1

The ball is launched from an initial height of 6.1 feet.

a net is a diagram that shows a “flattened” view of a solid. in a net, each face and base is shown with all of its dimensions. a net can also serve as a pattern to build a three-dimensional solid.

a pyramid is a three-dimensional object with a base that is a polygon and triangular faces that meet at one vertex.

" the net of a triangular pyramid consists of four triangles. the base here we are given of the pyramid is a equilateral   triangle, and the lateral faces are also triangles "

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step-by-step explanatio89