A portion of the graph of f(x) = −x2 + 6x − 5 is shown. Which of the following describes all solutions for f(x)? a partial parabola opening down and passing through 1 comma 0 and 5 comma zero with endpoints at 0 comma negative 5 and 6 comma negative 5 (x, y) for all real numbers (x, −x2 + 6x − 5) where 0 ≤ x ≤ 6 (x, −x2 + 6x − 5) where 1 ≤ x ≤ 5 (x, y) where 1 ≤ x ≤ 5

Step-by-step explanation:

Considering the function

solving

Similarly,

Also check the attached graph below.

From the graph as shown below, it is clear that

and

Also

Thus, from the figure, it is clear that a partial parabola opening down, passing through (1, 0) and (5, 0) with endpoints (0, -5) and (6, -5).

6 (3) - 4 + 32

hope this

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)