One leg of a triangle is 10 inches, and the hypotenuse is 12 what is the tangent of the triangles second smallest interior angle ?

Step-by-step explanation:

One leg of a triangle is 10  inches.

Hypotenuse is 12 inches.

To find the other leg, we apply the Pythagorean formula:

a² + b² = c² (Where a and b are the legs of a triangle and c is the hypotenuse)

So if we need to find the length of the other leg of our triangle, we do this;

a² = c² - b²

a² = 12² - 10² = 44

a = (the length of the shortest leg)

The shortest angle of this right-triangle is opposite to the shortest leg.

To find the tangent of this shortest angle, we divide;

Tan angle = opposite ÷ adjacent = ÷ 10 = (in surd form)

1/800 is the right answer

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet