Miguel is moving and wants to estimate what his electricity bill will be in his new apartment. He looks at old bills and sees that he uses around 700 kWh of electricity each month. The utility company charges $6 each month plus 6.726 cents per kWh for the first 500 kWhs and 8.136 cents for each kilowatt-hours above 500.How much will Miguel pay for 700 kWh of electricity?

$55.902

Step-by-step explanation:

To properly answer the question, we need to evaluate each of the payment conditions.

Firstly:

There is a $6 charge each month

Secondly:

For the first 500kwh, there is a charge of 6.726 cents per kWh.

Total amount charged here will be 500 * 6.726 = 3,363 cents = $33.63

Thirdly:

There is a charge of 8.136 cents for kwh above 500kwh. Here we have 200kwh more than the 500kwh threshold.

The amount charged here is thus 200 * 8.136 = 1627.2 cents = $16.272

Total amount charged is thus : 6 + 16.272 + 33.63 = $55.902

Miguel would pay $55.902

Step-by-step explanation:

The utility company charges $6 each month plus 6.726 cents per kWh for the first 500 kWhs and 8.136 cents for each kilowatt-hours above 500. Converting 6.726 cents and 8.136 cents to dollars, it becomes $0.06726 and 0.08136 respectively. This means that if Miguel uses x kilowatt-hours in a month, the total amount that he would pay is

6 + (500 × 0.06726) + 0.08136(x - 500)

= 6 + 33.63 + 0.08136(x - 500)

= 39.63 + 0.08136(x - 500)

Therefore, if Miguel uses 700 kWh of electricity, the total amount that he would pay is

39.63 + 0.08136(700 - 500)

= 39.63 + 0.08136 × 200

= 39.63 + 16.272

= $55.902

135 is your answer

step-by-step explanation:

try 180 times three then divide that number by 4 (sides) to get your answer. im glad to : )

correct answer is c. just did it

step-by-step explanation: