Suppose that only 25% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible. What is the probability that, of 20 ran- domly chosen drivers coming to an intersection under these conditions, a. At most 6 will come to a complete stop

The probability that at most 6 will come to a complete stop is 0.7857.

Step-by-step explanation:

Let X = number of drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

The probability of the event X is, P (X) = p = 0.25.

The sample of drivers randomly selected is of size, n = 20.

The random variable X follows a binomial distribution with parameters n = 6 and p = 0.25.

The probability function of  Binomial distribution is:

Compute the probability that at most 6 will come to a complete stop as follows:

P (X ≤ 6) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3)

                     + P (X = 4) + P (X = 5) + P (X = 6)

Thus, the probability that at most 6 will come to a complete stop is 0.7857.

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!