Use the quadratic formula to solve the equation, which has one solution. y^2+2y+1=0 Enter your answer in the box. Write the number only. Do not include "y =" in your answer.

the solutions the equation is - 3 or 5

Step-by-step explanation:

The given quadratic equation is expressed as

y² + 2y - 1 = 0

The equation is already in the standard form of ax² + bx + c

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 1

b = 2

c = - 1

Therefore, it becomes

= [- 2 ± √(2² - 4 × 1 × - 1)]/2 × - 1

= [- 2 ± (8)]/- 2

= (- 2 + 8)/ - 2. Or ( - 2 - 8)/ - 2

= 6/- 2 or - 10/- 2

= - 3 or 5

table 3 represents a direct variation function. : )