To keep the mass from accelerating, a spring is attached with spring constant k = 165 N/m. What is the coefficient of static friction if the spring must extend at least x = 12 cm from its unstretched length to keep the block from moving down the plane?

U = tantheta - KX/mgcostheta

Step-by-step explanation:

The formula for calculating the coefficient is given by.

KX = mgsintheta - mgucostheta

Making u subject of the formula we have

U = tantheta - KX/mgcostheta

K = 165N/m

X = 12 cm = 0.12m

U = tantheta - 165*0.12/mg*costheta

The question isn't complete but with this you can fix value for the mass and angle to get the final answer easily

they go with it happens or they mite give a chance?

step-by-step explanation:

the first option i believe

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