Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card and B be the analogous event for MasterCard. Suppose that P(A) = 0.6 and P(B) = 0.3.
a. What is the probability that the selected student has neither type of card?b. Describe in terms of A and B the event that the select student has a visa card, but not a mastercard? and then calulate the probability of this event. c. Calcuate th probability that the selected student has exactly one of the two types of cards?

a) Therefore, the probability is P=0.28.

b) Therefore, the probability is P=0.42.

c) Therefore, the probability is P=0.54.

Step-by-step explanation:

We know that A be the event that the selected student has a Visa card and B be the analogous event for MasterCard. Suppose that:

P(A) = 0.6 and P(B) = 0.3.

a) We calculate the probability that the selected student has neither type of card:

Therefore, the probability is P=0.28.

b) We calculate the probability that the select student has a visa card, but not a mastercard:

Therefore, the probability is P=0.42.

c) We calculate the probability  that the selected student has exactly one of the two types of cards:

Therefore, the probability is P=0.54.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

step-by-step explanation:

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