The time rate of change of a rabbit population P is proportional tothe square root of P. At time t = 0 (months) the populationnumbers 100 rabbits and is increasing at the rate of 20 rabbits permonth. How many rabbits will be there one year later?

121

Step-by-step explanation:

dP/dt is propotional to P^½

dP/dt = k(P^½)

When P=100, dP/dt=+20

20 = k(100^½)

20 = 10k

k = 2

dP/dt = 2(P^½)

Reciprocate both sides:

dt/dP = 1/[2(P^½)]

dt/dP = ½[P^(-½)]

Integrate wrt P.

t = ½ [(P^½) ÷ ½] + c

t = P^½ + c

Using t = 0, P =100.. find c

0 = 100^½ + c

0 = 10 + c

c = -10

t = P^½ - 10

Find P when t=1

1 = P^½ - 10

P^½ = 11

P = 121

50- 250 is correct i did that one too

step-by-step explanation: