A shipment of 20 similar laptop computers to a retail outlet contains 3 that are defective. If a school makes a random purchase of 2 of these computers, find the probability mass function for the number of defectives.

Step-by-step explanation:

Total number of laptops, N = 20

Defective laptops, n = 3

School purchase 2 laptops

Case 1:

Both laptops are non defective

Probability to choose 2 laptops which are non defective

Number of non defective laptops = 20 - 3 = 17

Total number of laptops = 20

Probability, P = 17/20 = 0.85

Case 2:

One laptop is defective

Probability to chose 1 defective and one non defective laptop

P' = 3/20 x 17/19 = 0.134

Case 3:

Both laptops are defective

Choosing of 2 laptops out of 3 = 3 C 2 = 3

choosing of 2 laptops out of 20 = 20 C 2 = 190

Probability of choosing two defective laptops = 3 / 190 = 0.0158

P'' =

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.