If the sum of three consecutive terms of GP are k-4,k, k+5. Find k

k = 20

Step-by-step explanation:

t1 = a = k-4

a = k - 4

t2 = ar = k

(k-4)r = k - 4

r = k/(k-4)

t3 = ar^2 = k + 5

(k - 4)(k/k - 4)^2 = k+5

k^2/k-4 = k+5

k^2 = (k+5)(k-4)

k^2 = k^2 -4k +5k -20

0 = k -20

k =20

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.