Pls answer! I don’t know math at all

The solutions of the system of equations are (–2, 4) or (–5, 1).

Solution:

Given equations are:

– – – – (1)

– – – – (2)

Equate the values of y.

Subtract 6 from both sides of the equation.

Subtract x from both sides of the equation.

Switch the sides.

Factor this polynomial, we get

x + 2 = 0 (or) x + 5 = 0

x = –2 (or) x = –5

Substitute x = –2 in equation (1),

y = –2 + 6

y = 4

Substitute x = –5 in equation (1),

y = –5 + 6

y = 1

The solutions of the system of equations are (–2, 4) or (–5, 1).

answer for #1 is c

answer for #2 is d

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