How do you solve this equation 27s-29=54s-83

s=2

Step-by-step explanation:

27s-29=54s-83

you want to get each variable on each side, so s on one side of the equal sign and the no variable on the other, but you can just put them there you can to add and subtract a variable of each side of them to get 0.

step 1.) 27s(-54s)-29=54s(-54s)-83

now you have -27s-29=-83, that's half of the equation done

step 2.) -27s-29(+29)=-83(+29)

you addition on this one because the even though it is a subtraction problem a - is always a negative number (think of it as adding a negative number)

you now have -27s=-54

step 3.) -27s/-27=-54/-27

at the end you (usually) always want the variable to be by itself so in this case s and on the left side. the answer is s=2

check.) you can check problems like this by substituting the variable for the number, so here is the check;

27x2-29=54x2-83

54-29=108-83

25=25

25 is the same as 25 which means that 2 is the correct answer

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's