Using the quadratic formula to solve x2 = 5 – x, what are the values of x? StartFraction negative 1 plus-or-minus StartRoot 21 EndRoot Over 2 EndFraction StartFraction negative 1 plus-or-minus StartRoot 19 EndRoot i Over 2 EndFraction StartFraction 5 plus-or-minus StartRoot 21 EndRoot Over 2 EndFraction StartFraction 1 plus-or-minus StartRoot 19 EndRoot i Over 2 EndFraction

StartFraction negative 1 plus-or-minus StartRoot 21 EndRoot Over 2

Step-by-step explanation:

The given quadratic equation is expressed as

x² = 5 - x

Rearranging the equation to take the standard form of ax² + bx + c, it becomes

x² + x - 5 = 0

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 1

b = 1

c = - 5

Therefore,

x = [- 1 ± √(1² - 4 × 1 × - 5)]/2 × 1

x = [- 1 ± √(1 - - 20)]/2

x = [- 1 ± √21]/2

x = (- 1 + √21)/2 or x = (- 1 - √21)/2

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

attachment?

step-by-step explanation: