Can someone help me with the extra credit

x = 64√13 / 9

Step-by-step explanation:

Starting at the top triangle, the hypotenuse is found with Pythagorean theorem:

c² = a² + b²

c² = 4² + 6²

c = √52

Moving on to the 30-60-90 triangle, the hypotenuse if found with trigonometry:

sin 60 = √52 / c

c = √52 / sin 60

c = √52 / (√3 / 2)

c = 2√(52/3)

Next is the 45-45-90 triangle.  The hypotenuse is again found with trig:

sin 45 = 2√(52/3) / c

c = 2√(52/3) / sin 45

c = 2√(52/3) / (√2 / 2)

c = 4√(26/3)

The next 30-60-90 triangle:

cos 30 = 4√(26/3) / c

c = 8√(26/9)

Another 30-60-90 triangle:

sin 60 = 8√(26/9) / c

c = 16√(26/27)

A 45-45-90 triangle:

sin 45 = 16√(26/27) / c

c = 32√(13/27)

The final 30-60-90 triangle:

sin 60 = 32√(13/27) / x

x = 64√(13/81)

x = 64√13 / 9

i dont get the question

step-by-step explanation: