A shoe manufacturer determines that its monthly revenue, R(q)=−0.31(q−260)^2+9500 in dollars, is given by the function defined above, where qqq is the number of pairs of shoes sold each month. What is the maximum value of the company's monthly revenue in dollars?

It should be noted that maximum value of the company's monthly revenue is $9500.

Therefore, the maximum value of the company's monthly revenue in dollars will be $9500.

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The maximum value of the company's monthly revenue is $9500.

Given to us,

shoe manufacturer monthly revenue =

where, q is the number of pairs of shoes sold each month,

To maximize the value of the company's monthly revenue, we need to differentitae the function,,

After diffrentiating it for the first time we get,

equating it against 0,

we get, q = 260,

Equating the value of q into the function we will get $9500.

Therefore, the maximum value of the company's monthly revenue is $9500, this happened because -0.31(q-260)² is negative we need to remove that value to get the maximum value.

Hence, the maximum value of the company's monthly revenue is $9500.

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solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake