Please help. I'm dumb and can't understand this.
In 2005 there were 11,700 students at college A, with a projected enrollment increase of 1000 students per year. In the same year, there were 32,100 students at college B, with a projected enrollment decline of 700 students per year.

A. In what year will the two colleges have the same enrollment?

B. At that time, how many students will be enrolled in the colleges?

A. 2073

B. 79700

Step-by-step explanation:

Let x represent the number of years that it will take the two colleges to have the same enrollment.

In 2005 there were 11,700 students at college A, with a projected enrollment increase of 1000 students per year. This means that the total number of students that would be enrolled at college A in x years time would be

1000x + 11700

In the same year, there were 32,100 students at college B, with a projected enrollment decline of 700 students per year. This means that the total number of students that would be enrolled at college B in x years time would be

700x + 32100

For the two colleges to have the same enrollment, then

1000x + 11700 = 700x + 32100

1000x - 700x = 32100 - 11700

300x = 20400

x = 20400/300

x = 68

The year would be 2005 + 68 = 2073

B) The number of students that will be enrolled in the colleges is

1000 × 68 + 11700

= 79700

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads