Y=0.006x^3 -0.06x^2+1.4x, x is horizontal, and y is vertical, is it possible for the vertical distance of the helicopter to be there times the horizontal distance

  yes (at about (22, 66)

Step-by-step explanation:

If you subtract 3 times the horizontal distance, the equation becomes ...

  yv -yh = (0.006x^3 -0.06x^2+1.4x) -(3x) = 0.006x^3 -0.06x^2 -1.6x

The signs of the terms are +--, so Descartes' rule of signs tells us the one sign change indicates one positive real root. That is this difference will be zero for some positive value of x.

Yes, it is possible.

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The graph shows the condition will be met near x=22.

javeir earned 56 dollors more than kyle so kyle and javier had 14w but javier made 56 dollors more so 14w plus 56 equals 70w so kyle has 14w

step-by-step explanation: hope i plz give me brainliest with the points so this is not constant cause it says last week so its clearly not every week