Which of these is the closest to DC, the height in feet, on the pole where the lower wire is attached ?

21.40 ft

Step-by-step explanation:

Angle BD is bisecting of ∠B, so we have to find ∠ B first. We have opposite(AC) and adjacent(BC) length, to find ∠B we can use tan formula.

tan ∠B= AC/BC

∠B= arctan(60ft/40ft)

∠B= 56.31 °

The ∠CBD bisect ∠B, so it equal to half of the angle. Angle CBD will be:

∠CBD= ∠B/2= 56.31 /2

∠CBD= 28.15 °

We have the angle(CBD) and adjacent(BC) length, now we can find DC using tan formula.

tan ∠CBD= DC/BC

DC= tan 28.15° * 40ft

DC= 0.53507226 * 40ft

DC= 21.40 ft

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.