According to data from the state blood program, 40 percent of all individuals have group A blood. Suppose that of six randomly selected individuals, three have group A blood. Would you believe the data from the blood program?a) Yes, probability is <.05 b) Yes, probability is > 05c) No

b. Yes, probability is > 0.05

Step-by-step explanation:

We have to find P(X=3) and if the probability is below 0.05 then the it would be unusual and if it isn't below 0.05 we believe that the data from the blood program.

This probability can be found bu binomial distribution  with parameters  n=6

and p=0.4.

P(X=x)=nCx(p^x)(q^n-x)

where q=1-p=1-0.4=0.6.

P(X=3)=6C3(0.4^3)(0.6^3)

P(X=3)=20(0.064)(0.216)

P(X=3)=0.27648

As the probability that the three have a blood group is greater than 0.05, so,  we believe that the data from the blood program.

u dumb boi

step-by-step explanation:

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4