Mike correctly found the slope and y-intercept of the line passing through the points (–5, –2) and (3, 14) as follows. m = StartFraction 14 minus (negative 2) Over 3 minus (negative 5) EndFraction = StartFraction 16 Over 8 EndFraction = 2. y = 2 x + b. Negative 2 = 2 (negative 5) + b. Negative 2 + 10 = negative 10 + b + 10. b = 8. What is the equation of the line in slope-intercept form?

Solution:

Mike correctly found the slope and y-intercept of the line passing through the points (–5, –2) and (3, 14)

To find:  Equation of the line in slope - intercept form

y = mx + c ------ eqn 1

Where, "m" is the slope of line and "c" is the y intercept

From given,

Therefore,

Thus slope of line is 2

Substitute m = 2 and (x, y) = (-5, -2) in eqn 1

-2 = 2(-5) + c

-2 = -10 + c

c = -2 + 10

c = 8

Substitute c = 8 and m = 2 in eqn 1

y = 2x + 8

Thus the equation of line is found

y=mx+b is the final answer!   : )