Which equation can be solved by using this system of equations?
[y= 3x2 - 7x2 + 5
Ly = 7x4 + 2x

Question:

Which equation can be solved by using this system of equations?

y = 3x^3 - 7x^2 + 5

y = 7x^4 + 2x

A.) 3x^3 - 7x^2 +5 = 0

B.) 3x^3 - 7x^2 + 5 = 7x^4 +2x

C.) 7x^4 +2x = 0

D.) 7x^4 +3x^3 -7x^2 +2x + 5 = 0

Option B: is used to solve this system of equations.

Explanation:

The two equations are and

Using substitution method, let us substitute in the equation , we get,

Thus,   is used to solve this system of equations.

Hence, Option B is the correct answer.

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

“ a line segment that has the endpoints on the circle and passes through the midpoint is called the diameter. the diameter is twice the size of the radius. a line segment that has its endpoints on the circular border but does not pass through the midpoint is called a chord. a circle is the same as 360 small circle up the number 0 . i hope this .