A ball is thrown vertically upward with an initial velocity of 3232 feet per second. The distance s (in feet) of the ball from the ground after t seconds is s equals 32 t minus 16 t squareds=32t−16t2. (a) At what time t will the ball strike the ground? (b) For what time t is the ball more than 1212 feet above the ground? A ball thrown vertically upward reaches a maximum before falling to the ground. A vertical line representing the height of the ball after t seconds is labeled s equals 32 times t minus 16 times t squared. A vertical line labeled 12 feet extends from the ground to a point slightly below the maximum height of the ball. s equals 32 t minus 16 t squareds=32t−16t2 12 ft12 ft (a) The ball will strike the ground when t is nothing seconds. (b) The ball is more than 1212 feet above the ground for the time t when nothingless than t less than