The stress matrix T referred to xyz-axes is shown below at the left (in kpsi). New x2-axes are chosen by rotating the axes as shown at the right. 「50 37.5 0 T= | 37.5-25-50 ー50 25 3 5 ㄎ (a) Determine the traction vectors on each of the new coordinate pla of components referred to the old axes. For example, determine t^z form t^z=( )i+( )j + ( )k. (b) Now project each of the vectors obtained in (a) onto the three new coordinate axes, and verify that the nine new components thus obtained for the stress matrix T are the same as those given by the formulas for transformation of a second-order tensor under rotation of axes.

i believe the answer to be 48

step-by-step explanation:

answer: 19 is   2

step-by-step explanation: i just looked at your answer and wrote it down

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

a

step-by-step explanation:

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