Find dy/dx if. y = inverse of cos x

dy/dx = -1 /√(1 - x^2).

Step-by-step explanation:

y = arccos x.

So x  = cos y

dx / dy = - sin y

dy / dx = -1 / sin y

But sin y = √( 1 - cos^2 y)

But cos y = x , so cos^2y = x^2

Therefore  

dy/dx = -1 / √(1 - x^2).

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

copyright potato 2019.

im guessing (23,14). hope this : )