An article gives arguments for why fracture toughness in concrete specimens should have a Weibull distribution and presents several histograms of data that appear well fit by superimposed Weibull curves. Consider the following sample of size n = 18 observations on toughness for high-strength concrete (consistent with one of the histograms); values of pi = (i − 0.5) 18 are also given. Observation 0.47 0.60 0.65 0.69 0.72 0.74 pi 0.0278 0.0833 0.1389 0.1944 0.25 0.3056 Observation 0.76 0.79 0.80 0.81 0.82 0.84 pi 0.3611 0.4167 0.4722 0.5278 0.5833 0.6389 Observation 0.86 0.89 0.91 0.95 1.01 1.05 pi 0.6944 0.75 0.8056 0.8611 0.9167
Construct a Weibull probability plot and comment.

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option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation:

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13