The sum of three consecutive numbers is 63, find the numbers

20, 21, and 22

Step-by-step explanation: This problem states that the sum of 3 consecutive numbers is 63 and it asks us to find the numbers.

First represent your numbers as follows.

X ⇒ first number

X + 1 ⇒ second number

X + 2 ⇒ third number

Since their sum is 63, our equation reads x + (x + 1) + (x + 2) = 63.

Simplifying on the left, we get 3x + 3 = 63.

Subtract 3 from both sides and 3x = 60.

Divide both sides by 3 and x = 20.

So our first number, x, is 20.

Our second number, x + 1 would then equal 21.

Our last number, x + 2, would be 22.

So our 3 consecutive numbers are 20, 21, and 22.

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204