You draw two cards from a standard deck of 52 cards. What is the probability of drawing a queen and then a king consecutively from the deck without replacement?

4/663

Step-by-step explanation:

There are 4 queens and 4 kings in a deck. Drawing a queen would be 4/52. Drawing a king afterwards with replacing the queen would be 4/51 because you took a queen but didn't replace that one queen card so the deck has only 51 cards left after you drew the queen. Drawing a queen would not affect your chance of drawing a king card, it will only affect the total number of cards left because you didn't replace the card afterwards. 4*4=16;52*51=2652. 16/2652 can be simplified to 4/663 by dividing 4 to both numbers. 16/4=4 and 2652/4=663. The probability of drawing a queen then a king without replacement would be 4/663.

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation:

236 cm 16 time 12 = 192

6 times 7 = 42

192+42