A researcher records the following scores on a working memory quiz for two samples. Which sample has a larger standard deviation? Sample A: 2, 3, 4, 5, 6, 7, and 8 Sample B: 4, 5, 6, 7, 8, 9, and 10

Standard deviations of both sets are equal

Step-by-step explanation:

We calculate the standard deviations for each sample set

For A

We calculate mean = (2+3+4+5+6+7+8)/7 = 35/5 = 7

We calculate deviations from the mean I.e each element in data set minus mean

x (x-mean)

2 -3

3. -2

4. -1

5. 0

6. 1

7 2

8. 3

If we look closely, we see that the sum of deviations is 0 , hence our standard deviation would be value zero too. This means there is no deviation about the mean

For the second set too, we calculate the mean = 4+5+6+7+8+9+10 = 49/7 = 7

We calculate the deviations too

X. X-mean

4. -3

5 -2

6 -1

7 0

8. 1

9 2

10. 3

Adding sum of deviations, we can see that the S.D is zero here too

Hence, the S.D of both data sets are equal

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.