G(x)=-3x
F(x)=x2+1
Find (g-f)(x)

-x² - 3x -  1

Step-by-step explanation:

g(x) = -3x; ƒ(x) = x²+ 1

(g - f)x = g(x) - ƒ(x)

(a) Write the two functions, one above the other, in decreasing order of exponents.

g(x) =     -3x

ƒ(x) = x²       +1

(b) Create a subtraction problem using the two functions

g(x) =     -3x

-ƒ(x) =  x²      +1

(c). Subtract terms with the same exponent of x

        g(x) =       -3x

       -ƒ(x) = x²        + 1

g(x) - ƒ(x) = -x² - 3x -  1

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option