A building is known to be 192 feet tall. A ball is dropped from the top of the building. In how many seconds will the ball hit the ground if the formula for the height of the ball at t seconds is given by h=192−16t2? Step 1 of 2 : First, what is the height of the ball when it hits the ground?

Step-by-step explanation:

The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.

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Using that in the equation, we can solve for t.

  0 = 192 -16t^2

  0 = 12 -t^2 . . . . . . divide by 16

  t^2 = 12 . . . . . . . . add t^2

  t = √12 = 2√3 ≈ 3.464 . . . . take the square root

It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.

the answer is b i just did that

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72