A sample of weights of defensive tackles on Big 10 football teams are: Johnson, 202 pounds; Patrick, 215 pounds; Junior, 207 pounds; Kendron, 212 pounds; Nicko, 214 pounds; and Cochran, 208 pounds. What is the sample standard deviation (in pounds)?

the sample standard deviation is 4.926 pounds

Step-by-step explanation:

the sample standard deviation s is defined as

s =√[ 1/(n-1) ∑ ( x- m)²]  for x=1 to x=n

where

n= sample size = 10

x= weights of defensive tackles

m= sample mean

m= 1/n ∑ x*  for x=1 to x=n

then

m= 1/10 (202 + 215... +208) = 209.66 pounds

thus

s =√[ 1/(10-1) ∑ ( x- m)²] = √[ 1/(10-1) [ ( 202 - 209.66 )² + ( 215 - 209.66 )² +  ( 28 - 209.66 )² ] ] = 4.926 pounds

then the sample standard deviation is 4.926 pounds

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step-by-step explanation:

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.