Mathematics, 13.02.2020 22:48 kokomolope
Shankar is teaching 2 courses, let us call them 435 and FYS. 435 has 3 sophomores, 8 juniors and 13 seniors; FYS has 5 sophomores, 7 juniors and 6 seniors. Suppose he wants to understand how his teaching is for the students. He picks one student from each class at random. Find the probability that both students are of the same type (i. e. both sophomores, or both juniors etc). Simplify your answer so it looks like a fraction without any factorials.
Answers: 1
.![=[(\frac{3}{24} )\times(\frac{5}{18})]+[(\frac{8}{24} )\times(\frac{7}{18})]+[(\frac{13}{24} )\times(\frac{6}{18})]\\=\frac{15+56+78}{432}\\ =\frac{149}{432}](/tpl/images/0510/5894/2084f.png)
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Shankar is teaching 2 courses, let us call them 435 and FYS. 435 has 3 sophomores, 8 juniors and 13...
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