The width of a rectangle is 28 cm. the perimeter of the rectangle is no more than 125cm. what is the largest possible length of the rectangle

34.5 cm

Step-by-step explanation:

Perimeter of rectangle = Length + Length + Width + Width

= 2Length + 2 Width

given width = 28 cm, equation becomes

Perimeter = 2Length + 2(28)

Perimeter = (2L + 56)  (eq1)

we are also given that the perimeter is no more than 125cm

this means that the perimeter is less than or equal to 125 cm i.e,

perimeter ≤ 125 cm

combining this with (eq 1) above,

(2L + 56) ≤ 125

2L + 56 ≤ 125  (subtract 56 from both sides)

2L ≤ 125 - 56

2L ≤ 69  (divide both sides by 2)

L ≤ 69 / 2

L≤ 34.5

hence the largest possibel length is 34.5 cm

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.