Which description is correct for the x-intercept(s) of Function A and Function B?

Function A:Function B:
f(x)=|x|−3

Function A has two x-intercepts.
Function B has one x-intercept.

Both functions have the same x-intercept(s).

Both functions have one negative and one positive x-intercept.

Function B has two x-intercepts.
Function A has one x intercept.

Step-by-step explanation:

Generally,

A straight line equation is given as

y = mx + c

Where,

m is the slope or gradient of the line

c is the intercept of y axis, when x = 0

Now,

Given the function A

g(x) = 0 7 0 2 -2

x = -2 3. 5 -1 0

So, we said the intercept c is when x = 0,

Therefore, in this case when x=0, g(x) = -2

Then, the intercept is -2 on y axis

Then, it has only one intercept, which is -2 on y-axis

To get the intercept on x axis, we will set y to zero,

In this case,

g(x) = 0, then, we have the intercept on x-axis to be -2 and 5

So it has 2-intercept on x axis, one positive and one negative

Given the function B

F(x) = |x| - 3

Comparing this to equation of a line, y= mx + c,

Then we notice that, the intercept is -3

Then, it has only one intercept which is -3 on y axis.

Now, to get the intercept on x axis, we will set f(x) = 0

F(x) = |x| - 3

0 = |x| - 3

Then, |x| = 3

Then, x = 3 or -x =3

Note that, |x| means x and -x

Then, x = 3 or x = -3

So it has also two intercept on the x axis, one positive and one negative.

Then, the third option is the correct option

Both functions have one negative and one positive x-intercept.

hello! just here for points! though i wish i knew!