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Mathematics, 13.02.2020 06:17 chem64
How many solutions will the equation
5(3x -9) = 2(6x + 9 ) have ?
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Answers: 2
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Prove (a) cosh2(x) โ sinh2(x) = 1 and (b) 1 โ tanh 2(x) = sech 2(x). solution (a) cosh2(x) โ sinh2(x) = ex + eโx 2 2 โ 2 = e2x + 2 + eโ2x 4 โ = 4 = . (b) we start with the identity proved in part (a): cosh2(x) โ sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 โ sinh2(x) cosh2(x) = 1 or 1 โ tanh 2(x) = .
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Daryl factors the polynomial p(x)=x3+x2โ26x+24 to rewrite it as p(x)=(x+6)(xโ4)(xโ1). which equations must be true? there may be more than one correct answer. select all correct answers. p(1)=0 p(โ4)=0 p(โ1)=0 p(6)=0 p(4)=0 p(โ6)=0
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How many solutions will the equation
5(3x -9) = 2(6x + 9 ) have ?...
5(3x -9) = 2(6x + 9 ) have ?...
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