How would you find g’(x)?

Step-by-step explanation:

Use the Second Fundamental Theorem of Calculus.

If g(x) = ∫ₐᵇ f(t) dt, then g'(x) = f(b) db/dx.

In this case, g(x) = ∫₁ˣ 1/t dt.  Therefore:

g'(x) = 1/x d(x)/dx

g'(x) = 1/x

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

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step-by-step explanation: