The larger of two numbers is 15 more than three times the smaller number. If the sum of the two numbers is 63, find the numbers

The smaller number equals 12, the larger number equals 51.

Step-by-step explanation:

x + (3x + 15) = 63

Combine like terms.

4x + 15 = 63

Subtract 15 from both sides.

4x + (15 -15) = (63 - 15)

4x = 48

Divide both sides by 4.

4x/4 = 48/4

x = 12

Check answer.

12 + (3(12) + 15) = 63

12 + 36 + 15 = 63

63 = 63

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116