The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6,008 kilograms per square centimeter and a standard deviation of 91 kilograms per square centimeter. Determine the probability a sample's strength is exactly 6,032 kilograms per centimeter squared. Round your answer to two decimal places.

0.60

Step-by-step explanation:

Mean m = 6008 kgcm-²

Standard deviation d = 91 kgcm-²

x = 6032 kgcm-²

P(z= 6032) = ¢(Z) = ¢( x-m/d)

P(z = 6032) = ¢ (6032-6008/91)

P(z = 6032)= ¢(0.264)

P(z= 6032) = 0.6026 = 0.60

Therefore, the probability a sample's strength is exactly 6,032 kilograms per centimeter squared is 0.60

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step-by-step explanation:

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