Lealie can run a 6 first mile, and 8 minutes for eac additional mile adterwards. Weseky can run. 9 mile, and 7 minutes for each additional mile. If they each ran for 1/2 an hour, who ran further? By how many miles? Write an equation and solve

Step-by-step explanation:

Distance = speed × time

Lealie can run a 6 first mile, and 8 minutes for each additional mile afterwards. This means that in x minutes after the first mile, the total distance that Lealie can run is

6 + x/8

Weseky can run. 9 mile, and 7 minutes for each additional mile. This means that in x minutes after the first mile, the total distance that Weseky can run is

9 + x/7

If they each ran for 1/2 an hour(30 minutes,

Total distance that Lealie would run is

6 + 30/8 = 6 + 3.75 = 9.75 miles

Total distance that Weseky would run is

9 + 30/7 = 9 + 4.29 = 13.29 miles

Therefore, Weseky ran further. The number of miles by which Weseky ran further is

13.29 - 9.75 = 3.54 miles

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.

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